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// Ex4_5
clc;
// Given:
t=5736;// in years
Nk=16.1;// dis/min
L=6.022*10^23;
// Solution:
k=(0.693*60)/(t*3.16*10^7);
N1=Nk/k;// atoms per g for C14
N2=L/12;//
r=(N1*10^12)/N2;// ratio of C14/C12 in atmosphere
printf("The ratio of C14/C12 in atmosphere in 10^-12 is = %f",r)
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