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+//chapter 2
+//R=l*sqrt(pi*F*Uo*Sigma)/Sigma*2*pi*r
+printf("\n");
+L=2;
+r=1*10^-3;
+f=2*10^6;
+u=4*(%pi)*10^-7;
+sig=5.7*10^6;
+R=sqrt((%pi)*2*10^6*4*(%pi)*10^-7/(5.7*10^6))*L/(2*(%pi)*10^-3);
+printf("the resistance of hertzian dipole is %gohm",R);
+dl=2
+frequency=2*10^6;
+lamda=3*10^8/(frequency);
+Rrad=80*(%pi)^2*(dl/lamda)^2;
+n=Rrad/(Rrad+R);
+printf("\nthe radiation efficiency is %gohm",n);