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+ // FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 2 : BESICS OF MAGNETIC CIRCUITS 
+// Example : 2.9
+clc;clear; // clears the console and command history 
+
+// Given data
+l = 0.45            // mean lenght in m
+A = 25*10^-4        // cross sectional area in m^2
+l_ag = 0.8*10^-3    // air gap in m
+N = 500            // number of turns 
+I = 1.25           // current in A 
+fulx = 2.25*10^-3  // flux in Wb
+phi = 1.5*10^-3   // flux in Wb
+
+// caclulations 
+B = phi/A                      // magnetic flux density in Wb/m^2
+MMF = N*I                      // magnetomotive force in At
+H = B/(4*%pi*10^-7)            // magnetomotizing force in At/m
+MMF_ag = H*l_ag                // magnetomotive force in At
+MMF_i = MMF-MMF_ag             // magnetomotive force for iron ring in At
+H_i = MMF_i/l                  // magnetic field intensity for iron part in At/m
+myu_r = B/((4*%pi*10^-7)*H_i)  // relative permiability for iron 
+
+// display the result 
+disp("Example 2.9 solution");
+printf(" \n Relative permiability for iron \n myu_r = %.2f  \n", myu_r);
+printf(" given current value in question is 2.25A, but in solution they took value of current as 1.25A ");