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+// FUNDAMENTALS OF ELECTICAL MACHINES 
+// M.A.SALAM 
+// NAROSA PUBLISHING HOUSE 
+// SECOND EDITION
+
+// Chapter 2 : BESICS OF MAGNETIC CIRCUITS 
+// Example : 2.10
+clc;clear; // clears the console and command history 
+
+// Given data
+A = 2*10^-4        // cross sectional area in m^2
+N = 200            // number of turns 
+flux = 1.5*10^-3   // flux in Wb
+myu_r = 4000       // relative permiability of core
+l_1 = 0.01         // length in m
+a = 9              // length in cm
+w = 3              // width in cm
+
+// caclulations 
+myu = myu_r*4*%pi*10^-7       // permiability 
+l_2 = (4*(a-w-w+(1.5+1.5))-1) // mean length in cm 
+R_mg = l_1/(4*%pi*10^-7*A)    // reluctance of iron for air gap At/Wb
+R_mi = l_2*10^-2/(myu*A)      // reluctance of iron for air gapAt/Wb
+R_mt = R_mg+R_mi              // total relectance in At/Wb
+I = R_mt*flux/N               // current in A 
+
+// display the result 
+disp("Example 2.10 solution");
+printf(" \n Current flowing through the coil \n I = %.0f A \n", I);
+
+// NOTE : In question they given flux=2.5mWb but in solution they took flux=1.5mWb