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+//Chapter-5,Example 3,Page 122
+clc();
+close();
+
+t=[75 119 183] //time in minute
+
+V=[24.20 26.60 29.32] //volume of alkali used
+
+V_0=19.24
+
+V_a=42.03
+
+k=(2.303 ./t).*log10((V_a-V_0)./(V_a-V))
+
+printf('values of k')
+
+disp(k)
+
+printf('since k values are fairly constant by putting in 1nd order rate equation. \nHence hydrolysis of methyl acetate is of 1st order.')