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//Chapter-5,Example 3,Page 122
clc();
close();
t=[75 119 183] //time in minute
V=[24.20 26.60 29.32] //volume of alkali used
V_0=19.24
V_a=42.03
k=(2.303 ./t).*log10((V_a-V_0)./(V_a-V))
printf('values of k')
disp(k)
printf('since k values are fairly constant by putting in 1nd order rate equation. \nHence hydrolysis of methyl acetate is of 1st order.')
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