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Diffstat (limited to '2459/CH22/EX22.8')
| -rw-r--r-- | 2459/CH22/EX22.8/Ex22_8.PNG | bin | 0 -> 4842 bytes | |||
| -rw-r--r-- | 2459/CH22/EX22.8/Ex22_8.sce | 22 |
2 files changed, 22 insertions, 0 deletions
diff --git a/2459/CH22/EX22.8/Ex22_8.PNG b/2459/CH22/EX22.8/Ex22_8.PNG Binary files differnew file mode 100644 index 000000000..debc43f77 --- /dev/null +++ b/2459/CH22/EX22.8/Ex22_8.PNG diff --git a/2459/CH22/EX22.8/Ex22_8.sce b/2459/CH22/EX22.8/Ex22_8.sce new file mode 100644 index 000000000..d6b92192a --- /dev/null +++ b/2459/CH22/EX22.8/Ex22_8.sce @@ -0,0 +1,22 @@ +//chapter22
+//example22.8
+//page496
+
+V_P=-5 // V
+V_DD=30 // V
+I_DSS=10 // mA
+I_D=2.5 // mA
+R1=1000 // kilo ohm
+R2=500 // kilo ohm
+
+// since I_D=I_DSS*(1-(V_GS/V_P))^2, making V_GS as subject we get
+
+V_GS=V_P*(1-(I_D/I_DSS)^0.5)
+
+V2=V_DD*R2/(R1+R2)
+
+// since V2 = V_GS + I_D*Rs, making Rs as subject we get
+
+Rs=(V2-V_GS)/I_D
+
+printf("required value of Rs = %.3f kilo ohm \n",Rs)
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