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+//chapter22
+//example22.8
+//page496
+
+V_P=-5 // V
+V_DD=30 // V
+I_DSS=10 // mA
+I_D=2.5 // mA
+R1=1000 // kilo ohm
+R2=500 // kilo ohm
+
+// since I_D=I_DSS*(1-(V_GS/V_P))^2, making V_GS as subject we get
+
+V_GS=V_P*(1-(I_D/I_DSS)^0.5)
+
+V2=V_DD*R2/(R1+R2)
+
+// since V2 = V_GS + I_D*Rs, making Rs as subject we get
+
+Rs=(V2-V_GS)/I_D
+
+printf("required value of Rs = %.3f kilo ohm \n",Rs)