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+//chapter1
+//example1.11
+//page20
+
+R1=4 // ohm
+R2=6 // ohm
+R3=5 // ohm
+R4=8 // ohm
+V=40 // V
+
+// load is removed and A and B are shorted
+load_source=R1+(R2*R3/(R2+R3)) 
+source_current=V/load_source 
+
+norton_current=source_current*(R2/(R2+R3)) // short circuit current in AB
+
+printf("shortcircuit current in AB = %.3f A \n",norton_current)
+
+// load is removed and battery is replaced by a short
+norton_resistance=R3+(R1*R2/(R1+R2))
+printf("norton resistance= %.3f ohm \n",norton_resistance)
+
+// equivalent circuit is norton current source in parallel with norton resistance
+I=norton_current*(norton_resistance/(norton_resistance+R4)) // current through 8 ohm resistance
+printf("current through 8ohm resistor = %.3f A",I)