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+//chapter1
+//example1.10
+//page18
+
+V=120 // V
+R1=40 // ohm
+R2=20 // ohm
+R3=60 // ohm
+
+//removing load, voltage across AB is
+E0=R2*V/(R1+R2)
+
+//replacing voltage source by short and removing load, resistance across AB is
+R0=R3+(R1*R2/(R1+R2))
+
+//for maximum power transfer, load must be equal to resistance across AB so
+Rl=R0
+
+P=E0^2/(4*Rl)
+printf("load resistance for maximum power transfer = %.3f ohm \n",Rl)
+printf("maximum power to load = %.3f W",P)