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diff --git a/2411/CH6/EX6.6/Ex6_6.sce b/2411/CH6/EX6.6/Ex6_6.sce
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+// Scilab Code Ex6.6: Page-348 (2008)
+clc; clear;
+MAX = 10;
+// Look for all the possible set of values for n1, n2 and n3
+printf("\nThe most probable distribution is for ");
+for i = 0:1:5  
+    for j = 0:1:5
+        for k = 0:1:5
+      // Check for the condition and avoid repetition of set of values
+            if ((i + j + k) == 5) & ((j+2*k) == 3) then 
+                W = factorial(i + j + k)/(factorial(i)*factorial(j)*factorial(k));
+                if W > MAX then
+                   printf("\nn1 = %d, n2 = %d and n3 = %d", i, j, k);
+                end
+            end
+        end
+    end
+end
+
+// Result
+// The most probable distribution is for 
+// n1 = 3, n2 = 1 and n3 = 1 
+\ No newline at end of file