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+clc
+clear
+//Input data
+d=25;//Diameter of the bore in cm
+l=0.4;//Stroke length in m
+N=300;//Operating speed of the engine in rpm
+n=120;//Number of explosions per minute
+pm=6.7;//Mean effective pressure in kgf/cm^2
+Tnet=90;//Net brake load in kg
+R=0.75;//Radius of brake drum in m
+f=0.22;//Fuel supplied per minute in m^3
+C=4500;//Calorific value of fuel in kcal/m^3
+
+//Calculations
+BHP=(2*3.14*R*N*Tnet)/4500;//Brake horse power in kW
+A=(3.14*d^2)/4;//Area of the cylinder in cm^2
+IHP=(pm*l*A*n)/4500;//Indicated horse power in kW
+H=f*C;//Heat supplied by fuel per minute in kcal
+nt1=((IHP*C)/(990*427))*100;//Thermal efficiency on IHP basis in percent
+nt2=((BHP*C)/(990*427))*100;//Thermal efficiency on BHP basis in percent
+
+//Output
+printf('(a)The brake horse power is %3.2f kW\n (b)Indicated horse power is %3.3f kW\n (c)Thermal efficiency on IHP basis is %3.2f percent\n (d)Thermal efficiency on BHP basis is %3.2f percent',BHP,IHP,nt1,nt2)