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+// Scilab code Exa10.3 : : Page-455 (2011)
+clc; clear;
+m_p = 1.007276; // Atomic mass of the proton, u
+m_H = 3.016049; // Atomic mass of the tritium, u
+m_He = 3.016029; // Atomic mass of the He ion, u
+m_n = 1.008665; // Atomic mass of the emitted neutron, u
+Q = (m_p+m_H-m_He-m_n)*931.5; // Q-value in MeV
+E_p = 3; // Kinetic energy of the proton, MeV
+theta = 30*3.14/180; // angle, radian
+u = sqrt(m_p*m_n*E_p)/(m_He+m_n)*cos(theta); //
+v = ((m_He*Q)+E_p*(m_He-m_p))/(m_He+m_n); //
+E_n = (u+sqrt(u^2+v))^2; // Kinetic energy of the emitted neutron,MeV
+printf("\nThe kinetic energy of the emitted neutron = %5.3f MeV", E_n);
+
+// Result
+// The kinetic energy of the emitted neutron = 1.445 MeV \ No newline at end of file