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+
+clear
+ clc
+//to find work done by the chid
+
+// GIVEN::
+
+//refer to figure 11-9(a) from page no. 233
+//mass of sled
+m = 5.6//in kg
+//distance by which sled is pushed horizontally
+s = 12//in meters
+//coefficient of kinetic friction
+mew_k = 0.20
+//angle made by the rope with horizontal
+fi = 45//in degrees
+//acceleration due to gravity
+g = 9.8//in m/s^2
+
+// SOLUTION:
+
+//refer to figure 11-9(b) from page no. 233
+//using newton's second law of motion
+//we get three equations and three unknowns
+A = [cosd(fi) -1 0;sind(fi) 0 1;0 1 -mew_k]
+B = [0; m*g; 0]
+c = A\B
+//force applied by the child
+F = c(1)//in N
+//frictional force 
+f = c(2)//in N
+//normal reaction
+N = c(3)//in N
+//work done by the child
+W = F*s*cosd(fi)//in J
+
+
+F = round(F)
+W = round(W)
+printf ("\n\n Force applied by the child F = \n\n %2i N",F);
+printf ("\n\n Work done by the child W = \n\n %3i J",W);