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+
+clear
+ clc
+//to find work done
+
+// GIVEN::
+
+//refer to figure 11-8(a) from page no. 232
+//mass of block
+m = 11.7//in kg
+//distance by which block is pushed on inclined plane
+s = 4.65//in meters
+//height by which block is raised
+h = 2.86//in meters
+//acceleration due to gravity
+g = 9.8//in m/s^2
+
+// SOLUTION:
+
+//refer to figure 11-8(b) from page no. 232
+//from diagram sin(theta) can be calculated as
+sin_theta = (h/s)
+//angle between applied force and displacement of block
+fi = 0//in degrees
+//using newton's second law of motion
+//force pushing the block 
+F = m*g*sin_theta//in N
+//work done by force F
+W = F*s*cosd(fi)//in J
+//work done by raising block vertically
+Work = m*g*h//in J
+W = round(W)
+Work = round(Work)
+printf ("\n\n Force pushing the block F = \n\n %.1f N",F);
+printf ("\n\n Work done by force F W = \n\n %3i J",W);
+printf ("\n\n Work done by raising block vertically \n\n Work = \n\n %3i J",Work);