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+// Example 8.1, page no-208
+clear
+clc
+d_cu=8.96*10^3//density of cu
+a_cu=63.55//Atomic weight of cu
+d_z=7100
+a_z=65.38
+d_al=2700
+a_al=27
+avg=6.023*10^26
+h=6.626*10^-34
+m=9.1*10^-31//kg
+e=1.6*10^-19//C
+
+//(i)
+n_cu=d_cu*avg/a_cu
+e_cu=(h^2/(8*m))*(3*n_cu/%pi)^(2/3)
+e_cu=e_cu/e
+printf("\n(i)For Cu\nThe electron concentration in Cu is %.4f*10^28 per m^3\nFermi energy at 0 k =%.4f eV ",n_cu*10^-28,e_cu)
+
+//(ii)
+n_z=d_z*avg*2/a_z
+e_z=(h^2/(8*m))*(3*n_z/%pi)^(2/3)
+e_z=e_z/e
+printf("\n(i)For Zn\nThe electron concentration in Zn is %.4f*10^28 per m^3\nFermi energy at 0 k =%.4f eV ",n_z*10^-28,e_z)
+
+//(i)
+n_al=d_al*avg*3/a_al
+e_al=(h^2/(8*m))*(3*n_al/%pi)^(2/3)
+e_al=e_al/e
+printf("\n(i)For Al\nThe electron concentration in Al is %.4f*10^28 per m^3\nFermi energy at 0 k =%.4f eV ",n_al*10^-28,e_al)