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-rwxr-xr-x182/CH7/EX7.1/7_1.txt2
-rwxr-xr-x182/CH7/EX7.1/example7_1.sce12
-rwxr-xr-x182/CH7/EX7.2/7_2.txt3
-rwxr-xr-x182/CH7/EX7.2/example7_2.sce17
-rwxr-xr-x182/CH7/EX7.3/7_3.txt4
-rwxr-xr-x182/CH7/EX7.3/example7_3.sce13
-rwxr-xr-x182/CH7/EX7.4/7_4.txt2
-rwxr-xr-x182/CH7/EX7.4/example7_4.sce16
-rwxr-xr-x182/CH7/EX7.5/7_5.txt1
-rwxr-xr-x182/CH7/EX7.5/example7_5.sce13
-rwxr-xr-x182/CH7/EX7.6/7_6.txt1
-rwxr-xr-x182/CH7/EX7.6/example7_6.sce18
-rwxr-xr-x182/CH7/EX7.7/7_7.txt2
-rwxr-xr-x182/CH7/EX7.7/example7_7.sce10
-rwxr-xr-x182/CH7/EX7.8/7_8.txt2
-rwxr-xr-x182/CH7/EX7.8/example7_8.sce13
16 files changed, 129 insertions, 0 deletions
diff --git a/182/CH7/EX7.1/7_1.txt b/182/CH7/EX7.1/7_1.txt
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index 000000000..ab4c60d74
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+++ b/182/CH7/EX7.1/7_1.txt
@@ -0,0 +1,2 @@
+
+1.The value of R=990 ohm \ No newline at end of file
diff --git a/182/CH7/EX7.1/example7_1.sce b/182/CH7/EX7.1/example7_1.sce
new file mode 100755
index 000000000..8a26fb8d0
--- /dev/null
+++ b/182/CH7/EX7.1/example7_1.sce
@@ -0,0 +1,12 @@
+// To find the value of measured Resistance R
+// example 7-1 in page 165
+clc;
+// Given data
+I=0.5;//measured current in amps
+V=500;// voltmeter indication in volts
+Ra=10;//ammeter resistance in ohms
+//calculation
+R=(V/I)-Ra;// measured resistance
+printf("The value of R=%d ohm",R);
+//result
+// The value of R=990 ohm \ No newline at end of file
diff --git a/182/CH7/EX7.2/7_2.txt b/182/CH7/EX7.2/7_2.txt
new file mode 100755
index 000000000..b65e71cde
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+++ b/182/CH7/EX7.2/7_2.txt
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+
+2.voltmeter reading-494 V
+Ammeter reading-0.500049 A \ No newline at end of file
diff --git a/182/CH7/EX7.2/example7_2.sce b/182/CH7/EX7.2/example7_2.sce
new file mode 100755
index 000000000..b0227e496
--- /dev/null
+++ b/182/CH7/EX7.2/example7_2.sce
@@ -0,0 +1,17 @@
+// To find the ammeter and ohmeter indication for the circuit 7-1(a)
+// example 7-2 in page 166
+clc;
+//Data given
+V=1000; S=10e+3; // voltmeter range and sensitivity in volt and ohm/volt
+R=990;// the resistance measured
+E=500;// supply voltage in volts
+Ra=10;// ammeter resistance in ohm
+//calculaTION
+Rv=V*S;// voltmeter resistance
+R1=(R*Rv)/(R+Rv);// as voltmeter is connected in parallel with the measured resistance, the equivalent resistance is the parallel combination of both resistancs
+Ev=(E*R1)/(R1+Ra);// voltmeter reading using voltage divider formula
+I=Ev/R1;// ammeter reading
+printf("voltmeter reading=%.0f V\nAmmeter reading=%.1f A\n",Ev,I);
+//result
+//voltmeter reading=495 V
+//Ammeter reading=0.5 A \ No newline at end of file
diff --git a/182/CH7/EX7.3/7_3.txt b/182/CH7/EX7.3/7_3.txt
new file mode 100755
index 000000000..bdc35b92a
--- /dev/null
+++ b/182/CH7/EX7.3/7_3.txt
@@ -0,0 +1,4 @@
+
+3.R from circuit 7-1(a)=990 ohm
+ R from circuit 7-1(b)=1000 ohm
+ thus circuit 7-1(a) gives the more accurate result \ No newline at end of file
diff --git a/182/CH7/EX7.3/example7_3.sce b/182/CH7/EX7.3/example7_3.sce
new file mode 100755
index 000000000..ecc1700c9
--- /dev/null
+++ b/182/CH7/EX7.3/example7_3.sce
@@ -0,0 +1,13 @@
+// To determine which of the circuits 7-1(a) or 7-2(b) has greater accuracy
+// example 7-3 in page 166
+clc;
+//Data given
+V1=495; I1=0.5; // voltmeter and ammeter reading in volt and ampere respectively of circuit 7-1(a)
+V2=500; I2=0.5;// voltmeter and ammeter reading in volt and ampere respectively of circuit 7-1(b)
+//calculation
+printf("R from circuit 7-1(a)=%d ohm\nR from circuit 7-1(b)=%d ohm\n",V1/I1,V2/I2);
+printf("thus circuit 7-1(a) gives the more accurate result");
+//result
+//R from circuit 7-1(a)=990 ohm
+//R from circuit 7-1(b)=1000 ohm
+//thus circuit 7-1(a) gives the more accurate result \ No newline at end of file
diff --git a/182/CH7/EX7.4/7_4.txt b/182/CH7/EX7.4/7_4.txt
new file mode 100755
index 000000000..90db497b1
--- /dev/null
+++ b/182/CH7/EX7.4/7_4.txt
@@ -0,0 +1,2 @@
+
+4.Measurement range is from 500 ohm to 4000 ohm \ No newline at end of file
diff --git a/182/CH7/EX7.4/example7_4.sce b/182/CH7/EX7.4/example7_4.sce
new file mode 100755
index 000000000..c9dbb4478
--- /dev/null
+++ b/182/CH7/EX7.4/example7_4.sce
@@ -0,0 +1,16 @@
+// to calculate the value of Resistance R
+// example 7-4 in page 169
+clc;
+// data given
+P=3.5e+3; Q=7e+3; S=5.51e+3; // resistance values of the wheatstone bridge arms in ohm
+//calculation
+R=S*P/Q;// equation for balancng condition
+printf("R=%f K-ohm\n",R/1000);
+S=[1e+3 8e+3];// adjusting s from 1 t0 8 K-ohm
+for n=1:2
+ R=S(n)*P/Q;
+ printf("when S=%d K-ohm,\n",S(n)/1000);
+ printf("R=%d ohm\n",R);
+end
+//result
+//Measurement range is from 500 ohm to 4000 ohm \ No newline at end of file
diff --git a/182/CH7/EX7.5/7_5.txt b/182/CH7/EX7.5/7_5.txt
new file mode 100755
index 000000000..d0384328f
--- /dev/null
+++ b/182/CH7/EX7.5/7_5.txt
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+5.the upper and lower limits of R are 2.760510 K-ohm and 2.749490 K-ohm respectively \ No newline at end of file
diff --git a/182/CH7/EX7.5/example7_5.sce b/182/CH7/EX7.5/example7_5.sce
new file mode 100755
index 000000000..5299e7046
--- /dev/null
+++ b/182/CH7/EX7.5/example7_5.sce
@@ -0,0 +1,13 @@
+// To calculate the accuracy of the measured value of resistance and to find the upper and lower values
+// example 7-5 in page 169
+clc;
+//Data given
+R=2.755e+3;//measured value of R in ohm
+E=[0.05 0.05 0.1]// percentage errors of the resistances P Q and S respectivly
+//calculation
+Re=sum(E);// percentage error in R
+Rmax=R+((Re/100)*R);//upper limit of resistance R in ohm
+Rmin=R-((Re/100)*R);// lower limit of resistance R in ohm
+printf("the upper and lower limits of R are %.4f K-ohm and %.4f K-ohm respectively",Rmax/1000,Rmin/1000);
+//result
+// the upper and lower limits of R are 2.760510 K-ohm and 2.749490 K-ohm respectively \ No newline at end of file
diff --git a/182/CH7/EX7.6/7_6.txt b/182/CH7/EX7.6/7_6.txt
new file mode 100755
index 000000000..3072cf314
--- /dev/null
+++ b/182/CH7/EX7.6/7_6.txt
@@ -0,0 +1 @@
+6.the minimum change in R which is detected by the bridge is 5.466141 ohm \ No newline at end of file
diff --git a/182/CH7/EX7.6/example7_6.sce b/182/CH7/EX7.6/example7_6.sce
new file mode 100755
index 000000000..561118190
--- /dev/null
+++ b/182/CH7/EX7.6/example7_6.sce
@@ -0,0 +1,18 @@
+// to calculate the minimum change detectable by the bridge
+// example 7-6 in page 172
+clc;
+//Given data
+P=3.5e+3; Q=7e+3; S=4e+3; R=2e+3; // bridge arm resistances in ohm
+Eb=10;// supply voltage in volt
+Ig=1e-6;//galvano meter reading in ampere
+rg=2.5e+3;//galvanometer resistance=2.5 K-ohm
+//calculations
+r=((P*R)/(P+R))+((Q*S)/(Q+S));// internal resistance of the bridge in ohm
+dVR=Ig*(r+rg);// open-circuit galvano meter voltage i,e VR-VS in volt
+VR=Eb*R/(R+P);// voltage across resistance R in volt
+VP=Eb-(VR+dVR);//voltage across resistance P in volt
+IR=VP/P;// current through P which is equal to current through R in ampere
+dR=((VR+dVR)/IR)-R;//Change in R value that the device can detect in ohm
+printf("the minimum change in R which is detected by the bridge is %f ohm\n",dR);
+//result
+// the minimum change in R which is detected by the bridge is 5.466141 ohm \ No newline at end of file
diff --git a/182/CH7/EX7.7/7_7.txt b/182/CH7/EX7.7/7_7.txt
new file mode 100755
index 000000000..ad7ca54a2
--- /dev/null
+++ b/182/CH7/EX7.7/7_7.txt
@@ -0,0 +1,2 @@
+
+7. the required ratio is 0.666667
diff --git a/182/CH7/EX7.7/example7_7.sce b/182/CH7/EX7.7/example7_7.sce
new file mode 100755
index 000000000..e323fb1bf
--- /dev/null
+++ b/182/CH7/EX7.7/example7_7.sce
@@ -0,0 +1,10 @@
+// to determinr the required ratio of R/P
+// example 7-7 in page 176
+clc;
+// Given data
+S=0.1; Q=0.15; // resistances in ohm
+//calculation
+r=S/Q;// here R/P=S/Q
+printf("the required ratio is %d/%d",(S*100),(Q*100));
+//result
+// the required ratio is 10/15 \ No newline at end of file
diff --git a/182/CH7/EX7.8/7_8.txt b/182/CH7/EX7.8/7_8.txt
new file mode 100755
index 000000000..6147b4818
--- /dev/null
+++ b/182/CH7/EX7.8/7_8.txt
@@ -0,0 +1,2 @@
+8.volume resistance=666666666 ohm
+ surface leakage resistance=285714285 ohm \ No newline at end of file
diff --git a/182/CH7/EX7.8/example7_8.sce b/182/CH7/EX7.8/example7_8.sce
new file mode 100755
index 000000000..58c2cb0dd
--- /dev/null
+++ b/182/CH7/EX7.8/example7_8.sce
@@ -0,0 +1,13 @@
+// to find the volume resistance and the surface leakage resistance
+// example 7-8 in page 180
+clc;
+//Data given
+Is=5e-6;// surface current in ampere
+Iv=1.5e-6;// volume current in ampere
+E=10000;// supply voltage in volt
+// calculation
+printf("volume resistance=%0.1e ohm\n",E/Iv);
+printf("surface leakage resistance=%0.1e ohm",E/(Is-Iv));
+//result
+//volume resistance=6.7e+009 ohm
+//surface leakage resistance=2.9e+009 ohm \ No newline at end of file
generated by cgit (git 2.34.1) at 2025-03-12 01:11:14 +0000