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diff --git a/181/CH6/EX6.21/example6_21.sce b/181/CH6/EX6.21/example6_21.sce
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+// Find operating region,Vgs,Vds,Id
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 6-21 in page 290
+
+clear; clc; close;
+
+// Given data
+K=0.2*10^-3; // Constant in mA/V^2
+Vt=1; // Voltage in V
+Vdd=10; // Drain voltage in V
+Rd=1*10^3; // Drain resistance in ohms
+
+// Calculation
+printf("(a)Vds=Vgs>Vgs-Vt.Hence active region operation\n");
+printf("0.2*Vgs^2+0.6*Vgs-9.8=0\n");
+Vgs1=(-0.6+sqrt(0.6^2-4*0.2*-9.8))/(2*0.2);
+Vgs2=(-0.6-sqrt(0.6^2-4*0.2*-9.8))/(2*0.2);
+printf("(b)Vgs = %0.2f V or %0.2f V\n",Vgs1,Vgs2);
+printf("Since 0<Vgs<10, Vgs = %0.2f V\n",Vgs1);
+Id=(Vdd-5.66)/Rd;
+printf("(c)Vds = Vgs = 5.66 V\n(d)Id = %0.2e A",Id);
+
+//Result
+// (a) The region of operation is active
+// (b) Vgs = 5.66 V
+// (c) Vds = 5.66 V
+// (c) Id = 4.34 mA
+\ No newline at end of file
diff --git a/181/CH6/EX6.21/example6_21.txt b/181/CH6/EX6.21/example6_21.txt
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+(a)Vds=Vgs>Vgs-Vt.Hence active region operation
+0.2*Vgs^2+0.6*Vgs-9.8=0
+(b)Vgs = 5.66 V or -8.66 V
+Since 0<Vgs<10, Vgs = 5.66 V
+(c)Vds = Vgs = 5.66 V
+(d)Id = 4.34e-003 A 
+\ No newline at end of file