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diff --git a/181/CH2/EX2.19/example2_19.sce b/181/CH2/EX2.19/example2_19.sce
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+// Factor to be multiplied with reverse saturation current
+// Basic Electronics
+// By Debashis De
+// First Edition, 2010
+// Dorling Kindersley Pvt. Ltd. India
+// Example 2-19 in page 98
+
+clear; clc; close;
+
+// Given data
+T1=25; // Initial temperature for Ge in degree celcius
+T2=70; // Final temperature for Ge in degree celcius
+T_2=150; // Final temperature for Si in degree celcius
+
+// Calculation
+printf("(a)Let the reverse saturation current for Ge at 25 degrees be Io(25)\n");
+A=2^((T2-T1)/10);
+printf("The factor to be multiplied when temperature is raised to 70 degrees is %0.0f\n",A);
+printf("Therefore, Io(70) = %0.0f*Io(25)\n\n",A);
+printf("(b)Let the reverse saturation current for Si at 25 degrees be Io(25)\n");
+A1=2^((T_2-T1)/10);
+printf("The factor to be multiplied when temperature is raised to 150 degrees is %0.0f\n",A1);
+printf("Therefore, Io(150) = %0.0f*Io(25)",A1);
+
+// Results
+// (a) Io(70) = 23*Io(25)
+// (b) Io(150) = 5793*Io(25)
+\ No newline at end of file
diff --git a/181/CH2/EX2.19/example2_19.txt b/181/CH2/EX2.19/example2_19.txt
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+(a)Let the reverse saturation current for Ge at 25 degrees be Io(25)
+The factor to be multiplied when temperature is raised to 70 degrees is 23
+Therefore, Io(70) = 23*Io(25)
+
+(b)Let the reverse saturation current for Si at 25 degrees be Io(25)
+The factor to be multiplied when temperature is raised to 150 degrees is 5793
+Therefore, Io(150) = 5793*Io(25) 
+\ No newline at end of file