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(a)Let the reverse saturation current for Ge at 25 degrees be Io(25)
The factor to be multiplied when temperature is raised to 70 degrees is 23
Therefore, Io(70) = 23*Io(25)

(b)Let the reverse saturation current for Si at 25 degrees be Io(25)
The factor to be multiplied when temperature is raised to 150 degrees is 5793
Therefore, Io(150) = 5793*Io(25)