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+clc
+clear
+//INPUT DATA
+//C4H10+6.5(O2+3.773N2) = 4CO2+5H2O+24.5245N2 ;//Chemicl equation
+x=0.9;//equivalent ratio
+
+//CALCULATIONS
+xs=(12*4+1*10)/(31.0245*28.962);//air fuel ratio
+xa=x*xs;//exhaust gas composition
+
+//OUTPUT
+printf('Exhaust gas compositin is %3.4f \n',xa)
+printf('C4H10+1.11*6.5( O2+3.773 N2) = 4 CO2+5 H2O+0.7150 O2+27.22 N2' )
+
+
+