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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1808/CH2/EX2.18/Chapter2_Example18.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '1808/CH2/EX2.18/Chapter2_Example18.sce')
-rw-r--r-- | 1808/CH2/EX2.18/Chapter2_Example18.sce | 16 |
1 files changed, 16 insertions, 0 deletions
diff --git a/1808/CH2/EX2.18/Chapter2_Example18.sce b/1808/CH2/EX2.18/Chapter2_Example18.sce new file mode 100644 index 000000000..2ee095647 --- /dev/null +++ b/1808/CH2/EX2.18/Chapter2_Example18.sce @@ -0,0 +1,16 @@ +clc
+clear
+//INPUT DATA
+//C4H10+6.5(O2+3.773N2) = 4CO2+5H2O+24.5245N2 ;//Chemicl equation
+x=0.9;//equivalent ratio
+
+//CALCULATIONS
+xs=(12*4+1*10)/(31.0245*28.962);//air fuel ratio
+xa=x*xs;//exhaust gas composition
+
+//OUTPUT
+printf('Exhaust gas compositin is %3.4f \n',xa)
+printf('C4H10+1.11*6.5( O2+3.773 N2) = 4 CO2+5 H2O+0.7150 O2+27.22 N2' )
+
+
+
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