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+
+
+                             // Examle 3.13
+
+                          // From Diagram (3.26) Apply KVL to get 24-4I-2I+18I= 0
+I=(-24/12);               // Current
+disp(' The value of Current = '+string(I)+' Amp');
+
+V1=4*I;                  // Voltage across 4 Ohm Resistor 
+p=-(4.5*V1*I);           // Power absorbed
+disp(' Power absorbed by dependent source = '+string(p)+' Watt');
+
+V=24;                    // Independent voltage source
+R=V/I;                   // Resistence Seen from Independent source
+disp(' Resistence Seen from Independent source = '+string(R)+' Ohm');
+
+
+
+
+                 //        p 67    3.13
+
+