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// Examle 3.13
// From Diagram (3.26) Apply KVL to get 24-4I-2I+18I= 0
I=(-24/12); // Current
disp(' The value of Current = '+string(I)+' Amp');
V1=4*I; // Voltage across 4 Ohm Resistor
p=-(4.5*V1*I); // Power absorbed
disp(' Power absorbed by dependent source = '+string(p)+' Watt');
V=24; // Independent voltage source
R=V/I; // Resistence Seen from Independent source
disp(' Resistence Seen from Independent source = '+string(R)+' Ohm');
// p 67 3.13
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