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+//Network Theorem 2
+//pg no 3.10
+//example 3.9
+//when 100 V source is acting alone
+disp("Vx-5I1=0");//equation 1
+disp("Applying KVL to mesh,");
+disp("10Vx-15I1=-100");//equation 2
+A=[1 -5;10 -15];//solving equation in matrix form
+B=[0 -100]'
+X=inv(A)*B;
+disp(X);//negative because of opposite direction
+disp("I1 = 2.857 A");
+//when the 10 A source is acting alone
+disp("9Vx+10I2=0");//equation 1
+disp("Applying KCL at Node 1,");
+disp("Vx=-100/7");//equation 2
+A=[9 10;1 0];//solving equation in matrix form
+B=[0 -100/7]'
+X=inv(A)*B;
+disp(X);
+disp("I2 = 12.857 A");
+a=2.857;
+b=12.857;
+x=a+b;
+printf("\nBy superposition theorem, \nI = I1+I2 = %.3f A ",x);