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+//Network Theorem 2
+//pg no 3.15
+//example 3.14
+//when 18 V source is acting alone
+disp("Vx1-31=0");//equation 1
+disp("Applying KVL to mesh,");
+disp("-3Vx1-9I=-18");//equation 2
+A=[1 -3;-3 -9];//solving equation in matrix form
+B=[0 -18]'
+X=inv(A)*B;
+disp(X);
+disp("Vx1 = 3 V");
+//when the 5 A source is acting alone
+disp("from the figure,");
+disp("V1+Vx2=0");//equation 1
+disp("Applying KCL at node 1,");
+disp("1/2V1-1/2Vx2=5");//equation 2
+A=[1 1;1/2 -1/2];//solving equation in matrix form
+B=[0 5]'
+X=inv(A)*B;
+disp(X);
+disp("Vx2= -5 V");
+//when the 36 V source is acting alone
+disp("from the figure,");
+disp("Vx3+3I=0");//equation 1
+disp("Applying KVL to the mesh,");
+disp("3Vx3-9I=-36");//equation 2
+A=[1 3;3 -9];//solving equation in matrix form
+B=[0 -36]'
+X=inv(A)*B;
+disp(X);
+disp("Vx3= -6 V");
+a=3;
+b=-5;
+c=-6;
+x=a+b+c;
+mprintf("\nBy superposition theorem, \n Vx = Vx1+Vx2+Vx3 = %.f V ",x);