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+//Network Theorem 2
+//pg no 3.14
+//example 3.13
+//when 120 V source is acting alone
+disp("Applying KVL to mesh,");
+disp("Iy1=5.45 A");
+//when the 12 A source is acting alone
+disp("from the figure,");
+disp("V1+4Iy2=0");//equation 1
+disp("Applying KCL at node 1,");
+disp("-V1/8 +9/4Iy2=-12");//equation 2
+A=[1 4;-1/8 9/4];//solving equation in matrix form
+B=[0 -12]'
+X=inv(A)*B;
+disp(X);
+disp("Iy2 =-4.36 A");
+//when 40 V source is acting alone
+disp("Applying KVL to mesh,");
+disp("Iy3=-1.82 A");
+a=5.45;
+b=-4.36;
+c=-1.82;
+x=a+b+c;
+mprintf("\nBy superposition theorem, \n I = Iy1+Iy2+Iy3 = %.2f A ",x);