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+//ques-18.43
+//Calculating equilibrium constant for dissociation of acetic acid
+clc
+T=298;//temperature (in K)
+R=8.314;//(in J/mol/K)
+//G = free energy change for formation (in kJ/mol)
+G1=-396.6;//acetic acid
+G2=-369.4;//acetate ion
+G3=0;//proton
+G=G2+G3-G1;//dissociation reaction
+c=-(G*1000)/(2.303*R*T);
+//On solving, log10(K) = c;
+K=1.72*10^-5;
+printf("The equilibrium constant for the reaction is %.7f.",K);