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+//EXAMPLE 26.24(b)
+//DC SHUNT MOTOR
+
+clc;
+funcprot(0);
+
+//Variable Initialisation
+V=500;..............................//Terminal voltage in Volts
+Il=5;..............................//Line current in Amperes
+Ra=0.15;...........................//Armature resistance in Ohms
+Rf=200;.............................//Field resistance in Ohms
+I=40;...............................//Load current in Amperes
+
+Ia=Il/2;..........................//Armature current in Amperes
+Lame=V*Ia;........................//Armature core loss and no load mechanical loss at rated speed in Watts
+Ita=I+Ia;.............................//Total current for armature in Amperes
+Lt=((Lame*2)+(Ra*Ita^2));................//Total losses in Watts
+Po=V*I*10^-3;................................//Output power in Kilo Watts
+y=round(Lt)/1000;...................................//Rounding of decimal places to Kilo Watts
+eff=Po*100/(Po+y);....................................//Efficiency in percentage
+y1=round(eff*100)/100;
+disp(y1,"Efficiency in percentage:");