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+// Example 5.8: VCEQ
+clc, clear
+VBE=-0.7; // in volts
+betaf=120;
+// From Fig. 5.19(a)
+VCC=18; // in volts
+R1=47e3; // in ohms
+R2=10e3; // in ohms
+RC=2.4e3; // in ohms
+RE=1.1e3; // in ohms
+// Using Thevnin's theorem to obtain equivalent circuit given in Fig. 5.19(b)
+VBB=R2*VCC/(R1+R2); // in volts
+RB=R1*R2/(R1+R2); // in ohms
+// Applying KVL in the base emitter loop and putting Ic= βF*Ib
+IB=(VBB+VBE)/(RB+(1+betaf)*RE); // in amperes
+IC=betaf*IB; // in amperes
+// In the collector emitter loop
+VCE=-VCC+IC*(RC+RE)+IB*RE; // in volts
+disp(VCE,"VCEQ (V) =");
+\ No newline at end of file