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+clc
+// Given that
+V = 1400 // volume of hall in meter^3
+C = 110 // seating capacity of hall
+a1 = 98 // area of plastered wall in m^2
+a2 = 144 // area of plastered ceiling in m^2
+a3 = 15 // area of wooden door in m^2
+a4 = 88 // area of cushioned chairs in m^2
+a5 = 150 // area of audience (each person) in m^2
+k1 = 0.03 // coefficient of absorption for plastered wall in O.W.U.
+k2 = 0.04 // coefficient of absorption for plastered ceiling in O.W.U.
+k3 = 0.06 // coefficient of absorption for wooden door in O.W.U.
+k4 = 1 // coefficient of absorption for cushioned chair in O.W.U.
+k5 = 4.7 // coefficient of absorption for audience (each person) in O.W.U.
+// Sample Problem 7 on page no. 8.20
+printf("\n # PROBLEM 7 # \n")
+printf(" Standard formula used \n")
+printf(" T = 0.161 V/a*S \n" )
+A1 = a1 * k1// calculation for the absorption by the plaster wall
+A2 = a2 * k2// calculation for the absorption by the plastered ceiling
+A3 = a3 * k3// calculation for wooden door
+A4 = a4 * k4// calculation for cushioned chairs
+A5 = C*k5 // the absorption due to persons
+A = A1 + A2 + A3 + A4 + A5 // calculation for total absorption
+T = (0.161 * V) / A// calculation for the reverberation time
+printf("\n Reverberation time is %f sec.",T)