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-rwxr-xr-x1271/CH14/EX14.25/25.txt5
-rwxr-xr-x1271/CH14/EX14.25/example14_25.sce16
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diff --git a/1271/CH14/EX14.25/25.txt b/1271/CH14/EX14.25/25.txt
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+ # PROBLEM 25 #
+Standard formula used
+ 1/2*m*v^2 = h*c*(1/lambda1 - 1/lambda2)
+
+ Wavelength of incident beam is 0.365115 Angstrom.
diff --git a/1271/CH14/EX14.25/example14_25.sce b/1271/CH14/EX14.25/example14_25.sce
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+clc
+// Given that
+E = 4 // enrgy of recoil electron in KeV
+theta = 180 // scattered angle of photon in degree
+h = 6.62e-34 // Planck constant in J-sec
+c = 3e8 // speed of light in m/sec
+e = 1.6e-19 // charge on an electron in C
+m = 9.1e-31 // mass of an electron in kg
+// Sample Problem 25 on page no. 14.30
+printf("\n # PROBLEM 25 # \n")
+printf("Standard formula used \n ")
+printf(" 1/2*m*v^2 = h*c*(1/lambda1 - 1/lambda2)\n")
+p = sqrt(2 * E * 10^3 * e * m)
+lambda = (2 * h * c) / (p * c + E * 10^3 * e)
+printf("\n Wavelength of incident beam is %f Angstrom.",lambda * 1e10)
+