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diff --git a/1223/CH3/EX3.17/Ex3_17.sce b/1223/CH3/EX3.17/Ex3_17.sce
new file mode 100755
index 000000000..4fc49d656
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+++ b/1223/CH3/EX3.17/Ex3_17.sce
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+clear;
+clc;
+//Example 3.17
+Vbe=0.7;
+Vcc=10;
+V2=5;
+b=100;
+R1=100;
+R2=50;
+Re1=2;
+Rth=R2*R1/(R1+R2);
+printf('\nThevenin rquivalent resistance=%.1f KOhm\n',Rth)
+Vth=(R2/(R1+R2))*Vcc-V2;
+printf('\nThevenin equivalent voltage=%.2f V\n',Vth)
+//Vth=Ib1*Rth+Vbe+Ie1*Re1-5 and Ie1=(1+b)*Ib1
+Ib1=(Vth+5-Vbe)/(Rth+(1+b)*Re1);
+printf('\nIb1=%.3f mA\n',Ib1)
+Ic1=b*Ib1;
+printf('\nIc1=%.3f mA\n',Ic1)
+Ie1=(1+b)*Ib1;
+printf('\nIe1=%.3f mA\n',Ie1)
+//summing the currents at the collector of Q1,Ir1+Ib2=Ic1
+//(5-Vc1)/Rc1+Ib2=Ic1
+//also Ib2=Ie2/(1+b)=(5-(Vc1+0.7))/(1+b)*Re2
+Rc1=5;
+Re1=2;
+Re2=2;
+Rc2=1.5;
+Vc1=Rc1*(1+b)*Re2*((5/Rc1)+(4.3/((1+b)*Re2))-Ic1)/(((1+b)*Re2)+Rc1);
+printf('\nVc1=%.2f V\n',Vc1)
+Ir1=(5-Vc1)/Rc1;
+printf('\nIr1=%.3f mA\n',Ir1)
+Ve2=Vc1+Vbe;
+printf('\nVe2=%.2f V\n',Ve2)
+Ie2=(5-Ve2)/Re1;
+printf('\nIe2=%.3f mA\n',Ie2)
+Ic2=Ie2*b/(1+b);
+printf('\nIc2=%.3f mA\n',Ic2)
+Ib2=Ie2/(1+b);
+printf('\nIb2=%f mA\n',Ib2)
+Ve1=Ie1*Re1-5;
+printf('\nVe1=%.2f V\n',Ve1)
+Vc2=Ic2*Rc2-5;
+printf('\nVc2=%.2f V\n',Vc2)
+Vce1=Vc1-Ve1;
+printf('\nVce1=%.2f V\n',Vce1)
+Vec2=Ve2-Vc2;
+printf('\nVec2=%.2f V\n',Vec2)