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-rwxr-xr-x1172/CH3/EX3.2/3_2.txt5
-rwxr-xr-x1172/CH3/EX3.2/Example3_2.sce11
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+ # Problem 2 #
+
+ Standard formula Used
+ E = h * (nu1 – nu2)
+ Energy of photoelectrons emitted is 1.031250 eV
diff --git a/1172/CH3/EX3.2/Example3_2.sce b/1172/CH3/EX3.2/Example3_2.sce
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+clc
+//Given that
+h = 6.6e-34 // plank's constant
+lambda_threshold = 2.4e-7 // threshold wavelength in cm
+lambda = 2e-7 // wavelength of irradicated light in photo emmission
+c = 3e8
+//Sample Problem 2 Page No. 135
+printf("\n # Problem 2 # \n")
+printf("\n Standard formula Used \n E = h * (nu1 – nu2)")
+E = h * c * ((lambda_threshold - lambda)/(lambda *lambda_threshold))/1.6e-19 // calculation of nergy of photoelectrons
+printf("\n Energy of photoelectrons emitted is %f eV", E)