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+// Electric Machinery and Transformers
+// Irving L kosow 
+// Prentice Hall of India
+// 2nd editiom
+
+// Chapter 1: Electromechanical Fundamentals
+// Example 1-6
+
+clear; clc; close; // Clear the work space and console.
+
+// Given data
+no_of_conductors = 40;
+I = 10; // Current carried by each condutcor
+R_per_path = 0.01; // Resistance per path
+flux_per_pole = 6.48 * 10 ^ 8; // flux lines 
+P = 2; // No. of poles
+path = 4; // No. of parallel paths
+total_flux = P * flux_per_pole; // Total flux linked in one revolution
+t = 2; // time for one revolution
+e_av_per_conductor = 6.48; // Average voltage generated per conductor
+
+// Calculations
+E_path = ( e_av_per_conductor ) * ( no_of_conductors / path ); // Average 
+//voltage  generated per path
+ 
+E_g = E_path; // Generated armature voltage
+
+I_a =( I / path ) * ( 4 * path ); // Armature current delivered to an external
+// load 
+
+R_a = ( ( R_per_path) / path ) * 10; // Armature resistance
+
+V_t = E_g - I_a * R_a; // Terminal voltage of generator
+
+P = V_t * I_a; // Genrator power rating
+
+// Display the results
+disp("Example 1-6 Solution");
+
+printf(" \n a : E/path = %.2f V/path ", E_path );
+printf(" \n b : Eg = %.2f V ", E_g );
+printf(" \n c : Ia = %.2f A ", I_a );
+printf(" \n d : Ra = %.3f ohm ", R_a );
+printf(" \n e : Vt = %.2f V ", V_t );
+printf(" \n f : P = %.2f W ", P );