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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /991/CH9/EX9.23/Example9_23.sce | |
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| -rwxr-xr-x | 991/CH9/EX9.23/Example9_23.sce | 50 |
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diff --git a/991/CH9/EX9.23/Example9_23.sce b/991/CH9/EX9.23/Example9_23.sce new file mode 100755 index 000000000..f1973f13c --- /dev/null +++ b/991/CH9/EX9.23/Example9_23.sce @@ -0,0 +1,50 @@ +//Example 9.23. refer fig.9.89
+clc
+VS1=60*10^-3
+VS2=40*10^-3
+hie=3.2*10^3
+hfe=100
+VEE=12
+VCC=VEE
+VBE=0.7
+beta=hfe
+RE=5.6*10^3
+RS=120
+RC=4.5*10^3
+Rc=4.5*10^-5
+format(6)
+IE=(VEE-VBE)/((2*RE)+(RS/beta))
+IE1=IE*10^3
+disp("beta = hfe = 100")
+disp(IE1," IE(mA) = (VEE-VBE) / ((2*RE)+(RS/beta))")
+IC=IE
+disp("IC ~ IE = 1.009 mA")
+disp(IE1," Therefore ICQ(mA) =")
+format(5)
+VCE=VCC+VBE-(IC*Rc)
+disp(VCE," VCE(V) = VCC + VBE - IC*RC =") // answer in textbook is wrong
+disp(VCE,"and VCEQ(V) =") // answer in textbook is wrong
+disp("The differential gain is")
+format(7)
+Ad=(hfe*RC)/(RS+hie)
+disp(Ad," Ad = hfe*RC / RS+hie =")
+disp("Common mode gain is,")
+format(7)
+AC=(hfe*RC)/(((2*RE)*(1+hfe))+RS+hie)
+disp(AC," AC = (hfe*Re) / (((2*RE)*(1+hfe)) + RS + hie) =")
+format(8)
+CMRR = Ad / AC
+disp(CMRR,"CMRR = Ad / AC =")
+format(7)
+CMRR1=20*log10(135.54/0.3966)
+disp(CMRR1,"CMRR(dB) = 20log|Ad/AC| =")
+disp("The output voltage is Vo = Ad*Vd + AC*VC. Here,")
+Vd=VS1-VS2
+Vd1=Vd*10^3
+disp(Vd1," Ad [mV(peak-peak)] = VS1 - VS2 =")
+VC=(VS1+VS2)/2
+VC1=VC*10^3
+disp(VC1,"Then, VC [mV(peak-peak)]= (VS1+VS2) / 2 =")
+format(5)
+Vo = Ad*Vd + AC*VC
+disp(Vo,"Therefore, Vo [V(peak-peak)] =")
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