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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /944/CH5/EX5.26 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
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Diffstat (limited to '944/CH5/EX5.26')
| -rwxr-xr-x | 944/CH5/EX5.26/example5_26_TACC.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/944/CH5/EX5.26/example5_26_TACC.sce b/944/CH5/EX5.26/example5_26_TACC.sce new file mode 100755 index 000000000..13204e17c --- /dev/null +++ b/944/CH5/EX5.26/example5_26_TACC.sce @@ -0,0 +1,22 @@ +//example 5.26
+
+
+clear;
+clc;
+
+//Given:
+T=169.25;//Boiling point[K]
+R=8.314;//Universal gas constant[J/K/mol]
+disp("dlnP/dT=He/R*T^2");
+disp("dlnP/dT=(2.303*834.13/T^2)+(1.75/T)-(2.30*8.375*10^-3)");
+disp("Therefore using these two equations we calculate the He(enthalpy) of ethylene");
+
+//To find the Enthalpy of vaporization of ethylene
+x=(2.303*834.13/T^2)+(1.75/T)-(2.30*8.375*10^-3);//it is dlnP/dT
+He=R*0.001*T^2*x;//Enthalpy of vaporization[J/mol]
+printf("\n\nThe Enthalpy of vaporization of ethylene at its boiling point is %f KJ/mol",He);
+
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+
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