From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 944/CH5/EX5.26/example5_26_TACC.sce | 22 ++++++++++++++++++++++
 1 file changed, 22 insertions(+)
 create mode 100755 944/CH5/EX5.26/example5_26_TACC.sce

(limited to '944/CH5/EX5.26')

diff --git a/944/CH5/EX5.26/example5_26_TACC.sce b/944/CH5/EX5.26/example5_26_TACC.sce
new file mode 100755
index 000000000..13204e17c
--- /dev/null
+++ b/944/CH5/EX5.26/example5_26_TACC.sce
@@ -0,0 +1,22 @@
+//example 5.26
+
+
+clear;
+clc;
+
+//Given:
+T=169.25;//Boiling point[K]
+R=8.314;//Universal gas constant[J/K/mol]
+disp("dlnP/dT=He/R*T^2");
+disp("dlnP/dT=(2.303*834.13/T^2)+(1.75/T)-(2.30*8.375*10^-3)");
+disp("Therefore using these two equations we calculate the He(enthalpy) of ethylene");
+
+//To find the Enthalpy of vaporization of ethylene
+x=(2.303*834.13/T^2)+(1.75/T)-(2.30*8.375*10^-3);//it is dlnP/dT
+He=R*0.001*T^2*x;//Enthalpy of vaporization[J/mol]
+printf("\n\nThe Enthalpy of vaporization of ethylene at its boiling point is %f KJ/mol",He);
+
+
+
+
+
-- 
cgit