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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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Diffstat (limited to '698/CH17/EX17.3')
-rw-r--r--698/CH17/EX17.3/3_gear_train.txt21
-rw-r--r--698/CH17/EX17.3/P3_gear_train.sce53
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diff --git a/698/CH17/EX17.3/3_gear_train.txt b/698/CH17/EX17.3/3_gear_train.txt
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+++ b/698/CH17/EX17.3/3_gear_train.txt
@@ -0,0 +1,21 @@
+(a)Gear diameters:
+ Da=210 mm
+ Db=390 mm
+ Dc=270 mm
+
+(b)Torque on shafts:
+ Mta=47.75 Nm
+ Mtb=0 Nm
+ Mtc=61.4 Nm
+
+(c)Tangential force on gear A: Ft=454 N
+ Separating force Fr=165 N
+
+(d)The same tangential and separating force occurs between gears
+A and B and between gears B and C.
+
+(e) The tooth load for which each gear must be designed is 454 N
+
+(f)The force applied to idler shaft of gear B is the vector sum
+of the forces applied to gear B by A and C
+Fb=sqrt(2*(Ft^2 + Fr^2))=684 N \ No newline at end of file
diff --git a/698/CH17/EX17.3/P3_gear_train.sce b/698/CH17/EX17.3/P3_gear_train.sce
new file mode 100644
index 000000000..a8b82d38e
--- /dev/null
+++ b/698/CH17/EX17.3/P3_gear_train.sce
@@ -0,0 +1,53 @@
+clc
+//Example 17.3
+//Gear train
+
+//------------------------------------------------------------------------------
+
+//Given data
+//Number of teeth
+Na=35
+Nb=65
+Nc=45
+//Speeds
+n=600 //rpm
+w=(2*%pi*n)/60
+//Power
+P=3000 //W
+//pressure angle
+phi=20
+//module
+m=6 //m
+
+res3=mopen(TMPDIR+'3_gear_train.txt','wt')
+
+//Gear diameters
+Da=Na*m
+Db=Nb*m
+Dc=Nc*m
+mfprintf(res3,'(a)Gear diameters:\n\tDa=%d mm\n\tDb=%d mm\n\tDc=%d mm\n\n',Da,Db,Dc)
+
+//Torque
+Mta=P/w
+Mtb=0
+Mtc=Mta* (Nc/Na)
+mfprintf(res3,'(b)Torque on shafts:\n\tMta=%0.2f Nm\n\tMtb=%d Nm\n\tMtc=%0.1f Nm\n\n',Mta,Mtb,Mtc)
+
+//Forces on gear A
+Ft=Mta/((Da/2)*10^-3)
+Fr=Ft*tand(phi)
+mfprintf(res3,'(c)Tangential force on gear A: Ft=%d N\n Separating force Fr=%d N\n\n',Ft,Fr)
+mfprintf(res3,'(d)The same tangential and separating force occurs between gears\nA and B and between gears B and C.\n\n')
+
+max_force=max(Ft,Fr)
+mfprintf(res3,'(e) The tooth load for which each gear must be designed is %d N\n\n',max_force)
+
+//Force applied to idler shaft
+Fb=sqrt(2*(Ft^2 + Fr^2))
+mfprintf(res3,'(f)The force applied to idler shaft of gear B is the vector sum\nof the forces applied to gear B by A and C\n')
+mfprintf(res3,'Fb=sqrt(2*(Ft^2 + Fr^2))=%d N',Fb)
+
+mclose(res3)
+editor(TMPDIR+'3_gear_train.txt')
+//------------------------------------------------------------------------------
+//-----------------------------End of program-----------------------------------