initial commit / add all books

author: prashantsinalkar 2017-10-10 12:27:19 +0530
committer: prashantsinalkar 2017-10-10 12:27:19 +0530
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tree: dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /656/CH1
parent: b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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diff --git a/656/CH1/EX1.1/example1_1.pdf b/656/CH1/EX1.1/example1_1.pdf
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diff --git a/656/CH1/EX1.1/example1_1.sce b/656/CH1/EX1.1/example1_1.sce
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+// e be the electron charge in coulombs (c)
+e=-1.6*10^-19;
+ 
+// n be the no. of electrons
+ 
+n=4600;
+ 
+//total charge q in coulombs (c)
+ 
+q=n*e;
+
+
+disp("q=")
+disp(q)
+units='coulombs C'; 
+q1=[string(q) units]; 
+disp(q1)
+// In coulombs
+
+
+// the total charge is -7.36*10^-16 coulombs
+
+
+
+
+
+
+
+ 
diff --git a/656/CH1/EX1.2/example1_2.pdf b/656/CH1/EX1.2/example1_2.pdf
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diff --git a/656/CH1/EX1.2/example1_2.sce b/656/CH1/EX1.2/example1_2.sce
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+// let q be the function of t q=f(t)
+ 
+deff('q=f(t)','q=5*t*sin(4*%pi*t)');
+
+//i is the current at t=0.5seconds in Amperes
+ 
+derivative(f,0.5);
+
+ i=ans;
+
+disp("i=")
+disp(i)
+units='Amperes A'
+i=[string(i) units];
+disp(i)
+// in amperes A
+
+ 
+// the current i is 31.415 Amperes
+
diff --git a/656/CH1/EX1.3/example1_3.pdf b/656/CH1/EX1.3/example1_3.pdf
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diff --git a/656/CH1/EX1.3/example1_3.sce b/656/CH1/EX1.3/example1_3.sce
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+// q be the charge in coulombs and i be the current in Ampere
+ 
+// i is given by i=(3*t^2-t)
+ 
+//charge is to be found between t=1s and t=2s
+ 
+integrate('3*t^2-t','t',1,2);
+ 
+// the charge between 1s and 2s is 5.5 coulombs
+ 
+q=ans;
+ 
+disp("q=")
+disp(q)
+units='Coulombs C'
+q=[string(q) units];
+disp(q)
+// in coulombs
+
+
+// the charge is 5.5 coulombs
diff --git a/656/CH1/EX1.4/example1_4.pdf b/656/CH1/EX1.4/example1_4.pdf
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diff --git a/656/CH1/EX1.4/example1_4.sce b/656/CH1/EX1.4/example1_4.sce
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+// i be the current in amperes i=2A
+ 
+// it flows for time t=10s
+ 
+// q be the total charge given  by q=i*t
+ 
+i=2;
+ 
+t=10;
+ 
+q=i*t;
+
+// total charge is 20 coulombs
+ 
+// energy is 2.3KJ ( kilo joules)
+ 
+w=2.3*10^3; 
+ 
+// voltage drop v in volts  given by= v=w/q
+ 
+v=w/q;
+
+disp("v=")
+disp(v)
+units='Volts V'
+v=[string(v) units];
+disp(v)
+// in volts V
+
+
+ 
+// voltage drop is 115v
+ 
diff --git a/656/CH1/EX1.6/example1_6.pdf b/656/CH1/EX1.6/example1_6.pdf
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diff --git a/656/CH1/EX1.6/example1_6.sce b/656/CH1/EX1.6/example1_6.sce
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+p=100;  
+ 
+t=2*3600;
+
+disp("t=")
+disp(t)
+// in seconds
+disp("sec")
+
+ 
+e=p*t;
+
+disp("e=")
+disp(e)
+units='Joules J'
+e1=[string(e) units];
+disp(e1)
+// in joules
+
+
+// energy is 720000joules
+ 
+ 
+
diff --git a/656/CH1/EX1.7/example1_7.pdf b/656/CH1/EX1.7/example1_7.pdf
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diff --git a/656/CH1/EX1.7/example1_7.sce b/656/CH1/EX1.7/example1_7.sce
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+//For p1, the 5-A current is out of the positive terminal (or into the negative terminal hence,
+
+// power(p) in watts is given by p=V*I
+
+// v voltage in volts and i current in Amperes 
+
+p1=20*-5;
+
+disp("p1=")
+disp(p1)
+units='Watts W'
+p1=[string(p1) units];
+disp(p1)
+
+// in watts
+
+ 
+// power in p1 is -100w ie. the supplied power
+ 
+//For p2 and p3, the current flows into the positive terminal of the element in each case. hence,
+ 
+p2=12*5;
+
+disp("p2=")
+disp(p2)
+units='Watts W'
+p2=[string(p2) units];
+disp(p2)
+
+// in watts
+ 
+ 
+// p2 is 60w absorbed power
+ 
+p3=8*6;
+
+disp("p3=")
+disp(p3)
+units='Watts W'
+p3=[string(p3) units];
+disp(p3)
+
+// in watts
+
+ 
+// p3 is absorbed power
+ 
+//For p4,we should note that the voltage is 8V(positive at the top), the same as the voltage for p3, since both the passive element and the dependent source are connected to the same terminals.
+ 
+// i current is 5A
+ 
+p4=8*(-0.2*5);
+
+disp("p4=")
+disp(p4)
+units='Watts W'
+p4=[string(p4) units];
+disp(p4)
+
+// in watts
+
+
+// p4 is -8w supplied power
+
+// now...
+p1=-100;
+p2=60;
+p3=48;
+p4=-8;
+
+p0=p1+p2+p3+p4;
+disp(p0)
+
+disp("W")
+// in watts W
+
+// this shows that total power supplied equals total power absorbed.
+ 
+
diff --git a/656/CH1/EX1.8/example1_8.pdf b/656/CH1/EX1.8/example1_8.pdf
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diff --git a/656/CH1/EX1.8/example1_8.sce b/656/CH1/EX1.8/example1_8.sce
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+// e be the charge of an electron e=-1.6*10^-19c
+ 
+// q be the charge, q=n*e where n is the no. of electrons
+ 
+// t is the time in seconds
+ 
+//i=q/t
+ 
+//i=(n*e)/t
+ 
+e=-1.6*10^-19;
+
+disp("e=")
+disp(e)
+// in coulombs C
+disp("C")
+ 
+n=10^15;
+
+disp(n)
+
+ 
+t=1;
+
+disp("t=")
+disp(t)
+// in seconds
+disp("sec")
+ 
+i=(n*e)/t;
+
+disp("i=")
+disp(i)
+// in amperes A
+disp("A")
+
+
+ 
+// i current is -0.00016A
+ 
+// power in watts P=V*I
+ 
+p=4;
+
+disp("p=")
+disp(p)
+// in watts W
+disp("W")
+
+ 
+ 
+v=p/i;
+
+disp("v=")
+disp(v)
+// in Volts V
+disp("V")
+
+ 
+// voltage needed to accelerate electron beam to 4w is 25000V
+ 
+V/1000;
+
+disp("V=")
+disp(V/1000)
+disp("KV")
+  
+ 
+// V is 25Kv
+ 
diff --git a/656/CH1/EX1.9/example1_9.pdf b/656/CH1/EX1.9/example1_9.pdf
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diff --git a/656/CH1/EX1.9/example1_9.sce b/656/CH1/EX1.9/example1_9.sce
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index 000000000..c775aed3a
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+// total power P consumed is 3300Kwh
+ 
+// base monthly charge BMH is 12$
+ 
+//First 100 kWh @ $0.16/kWh = $16.00 ; Next 200 kWh @ $0.10/kWh = $20.00; Remaining 100 kWh @ $0.06/kWh = $6.00
+ 
+charge=16+12+20+6;
+
+disp(charge) 
+units='Coulombs C'
+Q=[string(charge) units];
+disp(Q)
+// in coulombs C
+ 
+ 
+// total charge is 54$
+ 
+// avg cost AC is
+ 
+AC=charge/(100+200+100);
+
+disp(AC)
+units='Cents/KWH'
+AC=[string(AC) units];
+disp(AC)
+
+ 
+//13.5 cents/KWH
+ 
+
author	prashantsinalkar	2017-10-10 12:27:19 +0530
committer	prashantsinalkar	2017-10-10 12:27:19 +0530
commit	7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch)
tree	dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /656/CH1
parent	b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff)
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