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// i be the current in amperes i=2A
// it flows for time t=10s
// q be the total charge given by q=i*t
i=2;
t=10;
q=i*t;
// total charge is 20 coulombs
// energy is 2.3KJ ( kilo joules)
w=2.3*10^3;
// voltage drop v in volts given by= v=w/q
v=w/q;
disp("v=")
disp(v)
units='Volts V'
v=[string(v) units];
disp(v)
// in volts V
// voltage drop is 115v
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