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+//water chemistry//

+//example 7.15//

+W1=0.28;//amount of CaCO3 in grams dissolved in 1 litre of water//

+V1=28;//required EDTA in ml on titration of 100ml of CaCO3 solution//

+V2=33;//required EDTA in ml for 100ml of unknown hard water sample//

+V3=10;//required EDTA in ml for 100 ml of unknown sample after boiling and cooling//

+M1=100/100;//multiplication factor of CaCO3//

+C=W1*M1;

+printf("1 litre sample have %fg in terms of CaCO3",C);

+printf("\n1 ml sample have %fmgCaCO3",C);

+A=C*100//for 100 ml of sample equivalent to 28 ml of EDTA//

+B=A/V1;

+printf("\n1ml of EDTA=%fmg CaCO3",B);

+D=V2*B;//for 100 ml//

+D=D*1000/100;

+printf("\n1000ml of unknown water contains %fmgCaCO3",D);

+printf("\nTotal hardness is %fmg/lCaCO3 or ppm",D);

+E=V3*B;//for 100 ml//

+E=E*1000/100;

+printf("\n1000ml of boiled unknown water contains %fmgCaCO3",E);

+printf("\nPermanant hardness is %fmg/l CaCO3 or ppm",E);

+T=D-E;

+printf("\nTemporary hardness is %fmg/l CaCO3 or ppm",T);

+