From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 615/CH7/EX7.15/7_15.sce | 24 ++++++++++++++++++++++++
 1 file changed, 24 insertions(+)
 create mode 100755 615/CH7/EX7.15/7_15.sce

(limited to '615/CH7/EX7.15')

diff --git a/615/CH7/EX7.15/7_15.sce b/615/CH7/EX7.15/7_15.sce
new file mode 100755
index 000000000..6ae101a57
--- /dev/null
+++ b/615/CH7/EX7.15/7_15.sce
@@ -0,0 +1,24 @@
+//water chemistry//
+//example 7.15//
+W1=0.28;//amount of CaCO3 in grams dissolved in 1 litre of water//
+V1=28;//required EDTA in ml on titration of 100ml of CaCO3 solution//
+V2=33;//required EDTA in ml for 100ml of unknown hard water sample//
+V3=10;//required EDTA in ml for 100 ml of unknown sample after boiling and cooling//
+M1=100/100;//multiplication factor of CaCO3//
+C=W1*M1;
+printf("1 litre sample have %fg in terms of CaCO3",C);
+printf("\n1 ml sample have %fmgCaCO3",C);
+A=C*100//for 100 ml of sample equivalent to 28 ml of EDTA//
+B=A/V1;
+printf("\n1ml of EDTA=%fmg CaCO3",B);
+D=V2*B;//for 100 ml//
+D=D*1000/100;
+printf("\n1000ml of unknown water contains %fmgCaCO3",D);
+printf("\nTotal hardness is %fmg/lCaCO3 or ppm",D);
+E=V3*B;//for 100 ml//
+E=E*1000/100;
+printf("\n1000ml of boiled unknown water contains %fmgCaCO3",E);
+printf("\nPermanant hardness is %fmg/l CaCO3 or ppm",E);
+T=D-E;
+printf("\nTemporary hardness is %fmg/l CaCO3 or ppm",T);
+
-- 
cgit