From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 615/CH7/EX7.15/7_15.sce | 24 ++++++++++++++++++++++++ 1 file changed, 24 insertions(+) create mode 100755 615/CH7/EX7.15/7_15.sce (limited to '615/CH7/EX7.15') diff --git a/615/CH7/EX7.15/7_15.sce b/615/CH7/EX7.15/7_15.sce new file mode 100755 index 000000000..6ae101a57 --- /dev/null +++ b/615/CH7/EX7.15/7_15.sce @@ -0,0 +1,24 @@ +//water chemistry// +//example 7.15// +W1=0.28;//amount of CaCO3 in grams dissolved in 1 litre of water// +V1=28;//required EDTA in ml on titration of 100ml of CaCO3 solution// +V2=33;//required EDTA in ml for 100ml of unknown hard water sample// +V3=10;//required EDTA in ml for 100 ml of unknown sample after boiling and cooling// +M1=100/100;//multiplication factor of CaCO3// +C=W1*M1; +printf("1 litre sample have %fg in terms of CaCO3",C); +printf("\n1 ml sample have %fmgCaCO3",C); +A=C*100//for 100 ml of sample equivalent to 28 ml of EDTA// +B=A/V1; +printf("\n1ml of EDTA=%fmg CaCO3",B); +D=V2*B;//for 100 ml// +D=D*1000/100; +printf("\n1000ml of unknown water contains %fmgCaCO3",D); +printf("\nTotal hardness is %fmg/lCaCO3 or ppm",D); +E=V3*B;//for 100 ml// +E=E*1000/100; +printf("\n1000ml of boiled unknown water contains %fmgCaCO3",E); +printf("\nPermanant hardness is %fmg/l CaCO3 or ppm",E); +T=D-E; +printf("\nTemporary hardness is %fmg/l CaCO3 or ppm",T); + -- cgit