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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH20/EX20.16/20_16.sce | |
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initial commit / add all books
Diffstat (limited to '608/CH20/EX20.16/20_16.sce')
-rwxr-xr-x | 608/CH20/EX20.16/20_16.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/608/CH20/EX20.16/20_16.sce b/608/CH20/EX20.16/20_16.sce new file mode 100755 index 000000000..9cca90770 --- /dev/null +++ b/608/CH20/EX20.16/20_16.sce @@ -0,0 +1,22 @@ +//Problem 20.16: A 200 kVA rated transformer has a full-load copper loss of 1.5 kW and an iron loss of 1 kW. Determine the transformer efficiency at full load and 0.85 power factor.
+
+//initializing the variables:
+S = 200000; // in VA
+Pc = 1500; // in Watt
+Pi = 1000; // in Watt
+pf = 0.85; // power factor
+
+//calculation:
+//Efficiency = output power/input power = (input power—losses)/input power
+//Efficiency = 1 - losses/input power
+//Full-load output power = V*I*pf
+Po = S*pf
+//Total losses
+Pl = Pc + Pi
+//Input power = output power + losses
+PI = Po + Pl
+//efficiency
+eff = 1-(Pl/PI)
+
+printf("\n\n Result \n\n")
+printf("\n the transformer efficiency at full load is %.4f", eff)
\ No newline at end of file |