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+//Problem 13.18: (a) Convert the circuit to the left of terminals AB in Figure 13.45(a) to an equivalent Th´evenin circuit by initially converting to a Norton equivalent circuit. (b) Determine the current flowing in the 1.8 ohm resistor.

+

+//initializing the variables:

+E1 = 12; // in volts

+E2 = 24; // in volts

+R1 = 3; // in ohms

+R2 = 2; // in ohms

+R3 = 1.8; // in ohms

+

+//calculation:

+//For the branch containing the V1 source, converting to a Norton equivalent network gives

+Isc1 = E1/R1

+r1 = R1

+//For the branch containing the V2 source, converting to a Norton equivalent network gives

+Isc2 = E2/R2

+r2 = R2

+//Thus the network of Figure 13.46(a) converts to Figure 13.46(b).

+//total short-circuit current

+Isct = Isc1 + Isc2

+//the resistance is

+z = r1*r2/(r1 + r2)

+//Both of the Norton equivalent networks shown in Figure 13.46(c) may be converted to Th´evenin equivalent circuits. The open-circuit voltage across CD is

+Vcd = Isct*z

+//the current I flowing in a 1.8 ohm resistance connected between A and B is given by:

+I = Vcd/(z + R3)

+

+printf("\n\n Result \n\n") 

+printf("\n the current I flowing in a 1.8 ohm resistance connected between A and B is given by %.2f A",I)
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