From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 608/CH13/EX13.18/13_18.sce | 28 ++++++++++++++++++++++++++++ 1 file changed, 28 insertions(+) create mode 100755 608/CH13/EX13.18/13_18.sce (limited to '608/CH13/EX13.18/13_18.sce') diff --git a/608/CH13/EX13.18/13_18.sce b/608/CH13/EX13.18/13_18.sce new file mode 100755 index 000000000..69fd04087 --- /dev/null +++ b/608/CH13/EX13.18/13_18.sce @@ -0,0 +1,28 @@ +//Problem 13.18: (a) Convert the circuit to the left of terminals AB in Figure 13.45(a) to an equivalent Th´evenin circuit by initially converting to a Norton equivalent circuit. (b) Determine the current flowing in the 1.8 ohm resistor. + +//initializing the variables: +E1 = 12; // in volts +E2 = 24; // in volts +R1 = 3; // in ohms +R2 = 2; // in ohms +R3 = 1.8; // in ohms + +//calculation: +//For the branch containing the V1 source, converting to a Norton equivalent network gives +Isc1 = E1/R1 +r1 = R1 +//For the branch containing the V2 source, converting to a Norton equivalent network gives +Isc2 = E2/R2 +r2 = R2 +//Thus the network of Figure 13.46(a) converts to Figure 13.46(b). +//total short-circuit current +Isct = Isc1 + Isc2 +//the resistance is +z = r1*r2/(r1 + r2) +//Both of the Norton equivalent networks shown in Figure 13.46(c) may be converted to Th´evenin equivalent circuits. The open-circuit voltage across CD is +Vcd = Isct*z +//the current I flowing in a 1.8 ohm resistance connected between A and B is given by: +I = Vcd/(z + R3) + +printf("\n\n Result \n\n") +printf("\n the current I flowing in a 1.8 ohm resistance connected between A and B is given by %.2f A",I) \ No newline at end of file -- cgit