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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Calculate the dielectric stress, change in value of capacitance
+clc;
+L_air=(3.1-3)/2;
+D_stress=100/L_air;
+e0=8.85*10^-12;
+l=20*10^-3;
+D2=3.1;
+D1=3;
+C=(2*%pi)*e0*l/(log(D2/D1));
+disp(C,'Capacitance(F)=')
+l=(20*10^-3)-(2*10^-3);
+C_new=(2*%pi)*e0*l/(log(D2/D1));
+C_change=C-C_new;
+disp(C_change,'change in Capacitance(F)=')