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+clear;

+clc;

+printf("\n Example 10.3");

+

+//part 1

+//Solvent in underflow from final washing thickener = 50 kg/s.

+//The solvent in the overflow will be the same as that supplied for washing (200 kg/s).

+//Solvent discharged in overflow/Solvent discharged in underflow=  forthe washing thickeners.

+//Liquid product from plant contains 54.9 kg of salt in 195 kg of solvent.

+//This ratio will be the same in the underflow from the first thickener.

+printf("\n the material fed to the washing thickeners consists of 100 kg TiO2, 50 kg solvent and %d kg salt",50*(54.9/195));

+

+//m =n+1

+m = log(421)/log(4);

+printf("\n The required number of thickeners for washing are %f",m);

+

+//Part 2

+//From an inspection of the data, it is seen that Wh = 0.30 + 0.2Xh.

+//Thus: Sh = WhXh = 0.30Xh + 0.2X2h= 5Wh^2− 1.5Wh

+//Considering the passage of unit quantity of TiO2 through the plant, then:

+Ln = 0; wn = 2; Xn = 0;

+//since 200 kg/s of pure solvent is used.

+Sn = 0.001;

+Wn = 0.3007;

+So = 0.55;

+Wo = 1.00;

+//X1 = (Ln+1 + S0 − Sn)/(wn+1 + W0 − Wn)

+X1 = (0+0.55-0.001)/(2+1-0.3007);

+printf("\n concentration in the first thickener is %f",X1);

+

+W1 = 0.30+0.2*0.203;

+printf("\n W1 = %f",W1);

+S1 = (0.3406*0.203);

+printf("\n S1 = %f",S1);

+X2 = (0.0691 - 0.001)/(1.7 + 0.3406);

+printf("\n X2 = %f",X2);

+W2 = (0.30+0.2*0.0334);

+printf("\n W2 = %f",W2);

+X3 = (0.01025-0.001)/(1.7+0.3067);

+printf("\n X3 = %f",X3);

+printf("\n W3 = 0.30089");

+printf("\n S3 = %f",0.0013);

+printf("\n W4 = %f and S4 = %f",0.30003,0.000045);

+printf("\n Thus S4 is less than Sn and therefore 4 thickeners are required.");

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