From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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 542/CH10/EX10.3/Example_10_3.sci | 58 ++++++++++++++++++++++++++++++++++++++++
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+clear;
+clc;
+printf("\n Example 10.3");
+
+//part 1
+//Solvent in underflow from final washing thickener = 50 kg/s.
+//The solvent in the overflow will be the same as that supplied for washing (200 kg/s).
+//Solvent discharged in overflow/Solvent discharged in underflow=  forthe washing thickeners.
+//Liquid product from plant contains 54.9 kg of salt in 195 kg of solvent.
+//This ratio will be the same in the underflow from the first thickener.
+printf("\n the material fed to the washing thickeners consists of 100 kg TiO2, 50 kg solvent and %d kg salt",50*(54.9/195));
+
+//m =n+1
+m = log(421)/log(4);
+printf("\n The required number of thickeners for washing are %f",m);
+
+//Part 2
+//From an inspection of the data, it is seen that Wh = 0.30 + 0.2Xh.
+//Thus: Sh = WhXh = 0.30Xh + 0.2X2h= 5Wh^2− 1.5Wh
+//Considering the passage of unit quantity of TiO2 through the plant, then:
+Ln = 0; wn = 2; Xn = 0;
+//since 200 kg/s of pure solvent is used.
+Sn = 0.001;
+Wn = 0.3007;
+So = 0.55;
+Wo = 1.00;
+//X1 = (Ln+1 + S0 − Sn)/(wn+1 + W0 − Wn)
+X1 = (0+0.55-0.001)/(2+1-0.3007);
+printf("\n concentration in the first thickener is %f",X1);
+
+W1 = 0.30+0.2*0.203;
+printf("\n W1 = %f",W1);
+S1 = (0.3406*0.203);
+printf("\n S1 = %f",S1);
+X2 = (0.0691 - 0.001)/(1.7 + 0.3406);
+printf("\n X2 = %f",X2);
+W2 = (0.30+0.2*0.0334);
+printf("\n W2 = %f",W2);
+X3 = (0.01025-0.001)/(1.7+0.3067);
+printf("\n X3 = %f",X3);
+printf("\n W3 = 0.30089");
+printf("\n S3 = %f",0.0013);
+printf("\n W4 = %f and S4 = %f",0.30003,0.000045);
+printf("\n Thus S4 is less than Sn and therefore 4 thickeners are required.");
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-- 
cgit