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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /539/CH5/EX5.5/Example_5_5.sce | |
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Diffstat (limited to '539/CH5/EX5.5/Example_5_5.sce')
| -rwxr-xr-x | 539/CH5/EX5.5/Example_5_5.sce | 23 |
1 files changed, 23 insertions, 0 deletions
diff --git a/539/CH5/EX5.5/Example_5_5.sce b/539/CH5/EX5.5/Example_5_5.sce new file mode 100755 index 000000000..f16339a69 --- /dev/null +++ b/539/CH5/EX5.5/Example_5_5.sce @@ -0,0 +1,23 @@ +//Diffusion Coefficient Activation Energy and Preexponential Calculations
+
+clear;
+clc;
+
+printf("\tExample 5.5\n");
+
+//From graph log D ad 1/T are deducted
+inv_T1=0.8*10^-3; //Reciprocal of temp. in K^-1
+inv_T2=1.1*10^-3; //Reciprocal of temp. in K^-1
+logD1=-12.4;
+logD2=-15.45;
+
+R=8.31; //Gas law Constant in J/mol-K
+
+Qd=-2.3*R*(logD1-logD2)/(inv_T1-inv_T2);
+printf("\nActivation energy is %d kJ/mol",Qd/1000);
+
+//For calculating Peexponential factor
+D0=10^(logD2+(Qd*inv_T2/(2.3*R)));
+printf("\nPreexponential factor D0 is %.1f * 10^-5 m^2/s\n",D0/10^-5);
+
+//End
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